The 10-turn loop of wire shown in the figurelies in a horizontal plane, parallel to a uniform horizontal magnetic field, and carries a 2.0 A current. The loop is free to rotate about a nonmagnetic axle through the center. A 50 g mass hangs from one edge of the loop.
Torque = u * B
Torque = (I*A) B
The Attempt at a Solution
Ive tried all sorts of things I konw that I is 2.0 A and A is .1 * .05 so that gives .01 * B = Torque and Ive set torque equal to just the F of the weight times the radius and diameter and Ive also tried doubling the F because the force down on both sides. No matter what Ive tried it doesn't seem to work. Answers that I have gotten are 1.225. 2.45, 4.9, and .6125 so if you try this problem and get those they are wrong. Thanks for the help.
13.7 KB Views: 350