1. The problem statement, all variables and given/known data A potter's wheel of radius 0.50 m and mass 100.0 kg is freely rotating at 50.0 rev/min. The potter can stop the wheel in 6.0 seconds by pressing a wet rag against the rim. a. What is the angular acceleration of the wheel? b. How much torque does the potter apply to the wheel? 2. Relevant equations t=Ia a=w/t 3. The attempt at a solution a. (50/60*2*pi)=5.235988 rad/sec 5.235988/6=.87 rad/sec^2 b. I didnt understand this portion of the question. I tried .5^2*100*5.235988 but the answer was not 11 Nm which I know is the answer. Please help! Any help is greatly appreciated. Thank you.