(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A potter's wheel of radius 0.50 m and mass 100.0 kg is freely rotating at 50.0 rev/min. The potter can stop the wheel in 6.0 seconds by pressing a wet rag against the rim.

a. What is the angular acceleration of the wheel?

b. How much torque does the potter apply to the wheel?

2. Relevant equations

t=Ia

a=w/t

3. The attempt at a solution

a. (50/60*2*pi)=5.235988 rad/sec

5.235988/6=.87 rad/sec^2

b. I didnt understand this portion of the question. I tried .5^2*100*5.235988 but the answer was not 11 Nm which I know is the answer. Please help! Any help is greatly appreciated. Thank you.

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# Homework Help: Torque on potter's wheel

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