Torque on Wrench

  • Thread starter lacar213
  • Start date
  • #1
29
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Homework Statement


You want to exert a torque of at least 35.0 N·m on a wrench whose handle is 0.150 m long. If you can provide a force of 355 N to the end of the wrench, what is the minimum angle at which you can apply the force in order to achieve the desired torque?


Homework Equations


t = rfsinθ


The Attempt at a Solution


I am not sure how to rearrange this equation to find the angle or what other equation I have to use to find the angle.
torque = 35.0 NM
F = 355 N
M = .150 M
 

Answers and Replies

  • #2
152
0

Homework Statement


You want to exert a torque of at least 35.0 N·m on a wrench whose handle is 0.150 m long. If you can provide a force of 355 N to the end of the wrench, what is the minimum angle at which you can apply the force in order to achieve the desired torque?


Homework Equations


t = rfsinθ


The Attempt at a Solution


I am not sure how to rearrange this equation to find the angle or what other equation I have to use to find the angle.
torque = 35.0 NM
F = 355 N
M = .150 M
[tex]\vec{\tau}=\vec{r}\times\vec{F}\rightarrow\frac{\vec{\tau}}{rF}=\sin(\theta)[/tex]...
 
  • #3
29
0
After you divide the torque by the length and force do you take the sin of that answer - because when you do it is very small??
 
  • #4
152
0
After you divide the torque by the length and force do you take the sin of that answer - because when you do it is very small??
You apply the arcsin function to both sides of the equation, yielding:

[tex]\arcsin\left(\frac{\vec{\tau}}{rF}\right)=\theta[/tex].
 

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