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Torque problem help!

  1. Nov 20, 2012 #1
    1. The problem statement, all variables and given/known data

    Suppose the ruler in procedure 2 is asymetrical, and it is balanced at the 40.9 cm mark (at the center of mass). Now, mass M is hung on the ruler at the 100 cm mark. Where must you hang mass 1.42M so the system remains in equilibrium?
    At the .... cm mark

    2. Relevant equations

    Torque equations...

    3. The attempt at a solution

    I think it goes this way...

    1.42Mg(x) = Mg(100 - 40.9) where x is the distance from the 0 cm mark

    Then, I get x ≈ 41.6 cm, but it's marked incorrect.
     
  2. jcsd
  3. Nov 20, 2012 #2
    Wait. It's..

    1.42Mg(40.9 - x) = Mg(100 - 40.9)

    Then, I obtain negative value, which is around...

    x ≈ -0.720
     
  4. Nov 20, 2012 #3
    What is a difference between x = 41.6 cm and the negative value -0.72 cm? There should be a difference between them.
     
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