1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Torque Problem

  1. Dec 10, 2004 #1
    I have never really ever understtod the idea of torque correctly. I just cannot grab the concept. In this question the board is not moving, so the torque CCW must = torque CW...but how? as you can see I tried it, I only got 2/6 for marks on this question. What are the steps that I should take?

    [​IMG]
     
  2. jcsd
  3. Dec 10, 2004 #2

    Pyrrhus

    User Avatar
    Homework Helper

    This is obviously an equilibrium problem of rigid bodies.

    You need to apply this two conditions

    [tex] \sum_{i=1}^{n} \vec{F}_{i} = 0 [/tex]

    [tex] \sum_{i=1}^{n} \vec{\tau}_{i} = 0 [/tex]

    This is a simple 2 condition solution, if you pick as your origin the point where R1 is you can find R2, and then you could use as your origin R2, so you can find R1.
    Remember the weight of the board is at its center of gravity.

    You can pick any point as your origin for the 2nd condition and the torque sum will always be 0, there should be a proof of this in your text book, if you still want to know why, i can get into detail.
     
  4. Dec 10, 2004 #3

    Ok got that. Now waht Force would I use for R1 and R2. Would I add the person and the weight of the board together? Like say to get R1, Torque at R1 = F * LengthPerpendicular, so would I use 760N (the board and the person)?
     
  5. Dec 10, 2004 #4

    Pyrrhus

    User Avatar
    Homework Helper

    No, you don't add the weight of the person and the board together...

    You find each of the torque's for all the forces at the R1 force position as your origin, give each of the torques its sign by using the right hand rule, and add them algebraicly.

    Remember

    [tex] \vec{\tau} = \vec{r} \times \vec{F} [/tex]
     
  6. Dec 11, 2004 #5
    this appears to be a simple question, you can take torques at R1, and use the condition that Tcw = Tccw to solve. you know Fbeam + Fperson + R2 = R1, so after you get R1 or R2 you can easily solve for the other
     
    Last edited: Dec 11, 2004
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Torque Problem
  1. Pulley Torque Problem (Replies: 1)

  2. Torque problem (Replies: 4)

  3. Torque problem (Replies: 11)

Loading...