- #1

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Perhaps I cannot visualize the question, but I cannot see how this can be. As the force moves to the perpendicular position the torque increases. Am I missing something?

- Thread starter Ronnin
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- #1

- 168

- 0

Perhaps I cannot visualize the question, but I cannot see how this can be. As the force moves to the perpendicular position the torque increases. Am I missing something?

- #2

- 2,063

- 2

Use the definition of torque. If one angle between the p.v and force vector is theta, what about the other?

Edit: I guess this holds only for the magnitude of the torque.

Edit: I guess this holds only for the magnitude of the torque.

Last edited:

- #3

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[tex] \tau = rF \sin \theta [/tex]

[tex]sin \theta = \sin (\pi - \theta)[/tex]

[tex]sin \theta = \sin (\pi - \theta)[/tex]

- #4

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I guess I figured that would put the angle outside of between the two angles.

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