I have the hardest homework ever for my college (algebra-based) physics class (took 4 hours for 8 problems!!) and I really need some help understanding how these problems work. The one's I can't get are all related so if I figure out one I can get more. It's all related to torque, inertia, etc. One that I'm having the most problems with is: A shop sign weighing 214 N is supported by a uniform 144N beam of length L=1.90 m. There is a guy wire connected D=1.20m from the backboard. Find the tension in the guy wire. Assume theta=39.5degrees. (the right angle of the right triangle made by the guy wire and the beam is against the wall of the building in the drawing). So what I have so far is that I know I need to find all the forces for Fx and for Fy. The tension (T) points upwards on the guy wire, in the negative x direction. The weight of the beam and the weight of the sign are also forces pointing downwards in the negative y direction. For Fx, I know for sure that Fx= -Tcos(theta) and there is also a force in the horizontal direction at the hinge of the beam and the wall. For Fy, I know that Fy= -Weight(beam) - Weight(sign)-Tsin (theta) and there is a vertical force in the positive y direction at the hinge. I get stuck at where the length comes into play when solving the equations and what do do because the guy wire isn't connected at the end of the beam, only 1.20 m down it. Can anyone give me some hints?!?! Thank you!