- #1
Drespar
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Homework Statement
A safe is in the back of a truck resting against a ledge that is .0381 m high. The truck is traveling at a velocity of approx. 29.1 m/s (about 65 mph). The driver then is forced to make an emergency stop, causing a negative acceleration of -6.86 m/s2. (solved for the acceleration with friction and velocity).
What will the safe do?
The safe's mass: 1063kg
Friction Coefficient (safe on truck bed): .8
Homework Equations
Force(net)x = 0
Force(net)y = 0
Torque(net) = r χ F
The Attempt at a Solution
As it stands, I have tried to construct an extended Force & Torque diagram. The pivot point of the system is located at the top of the ledge. The object is not accelerating in either the x or y direction so the net force in those directions is 0.
My main issue, is why is the normal force shifted (I have looked for explanations, they show the normal force has shifted towards the pivot, but they don't say why). Additionally, I do not know how to solve the equation for the minimum force required to tip the safe.