1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Torque/Rigid body rotation

  1. Aug 30, 2012 #1
    1. The problem statement, all variables and given/known data
    This is problem 7.7 from [kleppners mechanics book]http://books.google.ie/books?id=Hmq...rough a point on the rim of the hoop"&f=false but its also a general question on understanding this type of problem.

    2. Relevant equations
    L=Iω
    dL/dt=ΩL=rxF


    3. The attempt at a solution

    The standard approach appears to be compute the angular momentum from Iω and find how it changes with respect to time, generally its ΩL where Ω is the precession about the axis, then compute the relevant torque and set them equal and solve for whatever your looking for.


    My problems arises in 7.7 as the force creating the torque(the tension in the string) is at an angle to axis and the r from r x F is also at angle to the axis. So I'm not quite sure how I get the relevant force, I'm thinking it's as simple as r x (perp component of T) but I'm not 100%.

    I'm also not sure since, I'm breaking down ω as a vector into components, perp and parallel to the hoop, then computing the spin angular momentum from the perp ω and ignoring the parallel ω one. But I'm not sure if you can just do that in this problem because the way the torque is setup, maybe I need to include the other component of angular momentum into it?.

    Help would be much appreciated.

    As they say solve it approximately with small angles, I assume that means cosx=1 and sinx=x


    Right now for dL/dt i.e ΩL I have MR^2 ω^2 β
    and for the torque I have with T=Mg torque=RMg(1+αβ)
     
  2. jcsd
  3. Aug 31, 2012 #2
    Google does not want to show that part of book anymore. You will have to reproduce the problem here to get any help.
     
  4. Aug 31, 2012 #3
    Really? It shows me it just fine when I click on the link

    http://www.maths.tcd.ie/~kovacs/Teaching/Mechanics/Kleppner-Kolenkow.pdf [Broken]

    page 352 question 7.7
     
    Last edited by a moderator: May 6, 2017
  5. Sep 1, 2012 #4
    I have looked through the whole chapter in the book, and I have a question: how is the hoop different from a gyroscope tilted down?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Torque/Rigid body rotation
  1. Torque on a rigid body (Replies: 1)

  2. Rigid Body Rotation (Replies: 1)

Loading...