1. The problem statement, all variables and given/known data A 6 meter long ladder rests against a wall which is 4 m tall. The base of the ladder is 1.5 m away from the base of the wall (in the picture you can see the wall touches the ladder about 3/4 way up the ladder). The wall is frictionless, but the ground is not. a- Find the normal force on the ladder due to the wall (remember it is perpendicular to the ladder) b- Find the normal force on the ladder due to the ground. c- If the ladder is just about to slide, find the coefficient of static friction between the wall and the ground. 2. Relevant equations torque = r * force * sin (angle between them) 3. The attempt at a solution a- I put the pivot at the point where the floor meets the ladder. I found the angle to be 69.5 -torque of normal wall - torque of weight = 0 r*normal wall * sin 90 = r*weight * sin 200.5 normal wall = 17.2 N b- I put the pivot at the point where the wall meets the ladder. torque of normal floor - torque static friction - torque weight = 0 I dont know normal floor or friction force, so how do I solve this?