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## Homework Statement

(This is a continuation of the problem where I proved Torricelli's Law: v =

**√**(2gh))

The water level in a tank lies a distance

*H*above the floor. There is a hole in the tank that a distance

*h*below the water level

a.) Find the distance

*x*from the wall of the tank at which the leaked stream of water hits the floor

b.) Could another hole be punched at another depth

*h'*so that this second stream would have the same range? If so, at what depth?

## Homework Equations

Δx = (v

_{f}

^{2}- v

_{i}

^{2})/g

v =

**√**(2gh)

## The Attempt at a Solution

At first, I was not really sure what to do here at all (and I probably ended up solving it completely wrong.)

So, basically, I wasn't exactly sure how to find the distance, since I only knew the initial velocity in the x direction (or, at least, I assumed v =

**√**(2gh)) was the velocity of the water in the x direction based off the picture in the problem.)

So, what I tried was:

(Since the equation I had to derive from Torricelli's law in the problem I had to do before this ended up being Δv =

**√**(2gh), I assumed:)

Δx = (2gh)/g

= 2h

For b, I'm completely confused on even where to begin solving for the equation.