the pulley, object a and object b all have the same mass
The cylinder rotates without sliding
He asked for the cylinder's acceleration in m(mass),g(gravitation), r(radius) variables
The Attempt at a Solution
Okay, so my teacher said that the frictional force oppose the line tension,
[tex]\sum torque=(line tension2 . radius) - (frictionalforce . radius) = m.a[/tex]
Line tension1 - weight = m . a
what I don't get is why my teacher said that object a's acceleration is the total of its tangential acceleration and its linear acceleration.