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Total Angular Momentum of a dumbbell

  1. Apr 6, 2008 #1
    1. The problem statement, all variables and given/known data
    A dumbbell consists of two small balls attached to the ends of a 1.0m rod of negligible mass. Ball1 has a mass of 1.0kg and ball2 has a mass of 3.0kg. The dumbbell rotates about a fixed vertical axis midway between the balls, with an angular speed of 1/pi rev/s. What is the total angular momentum of the dumbbell?


    2. Relevant equations


    3. The attempt at a solution

    I=mr^2
    L=wI
    w=2 (since the angular speed is 1/pi rev/s?)
    r^2=0.25m
    m=4kg
    L=2 kg*m²/s
    would that be right?
     
  2. jcsd
  3. Apr 6, 2008 #2
    Seems OK to me.
     
  4. Apr 6, 2008 #3
    Perfect.
     
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