I'm trying to solve the problem but keep getting the wrong answer. Could someone help please? s = (v^2sin2t)/g where s = horizontal distance, v = initial velocity, t = angle, g = acc. gravity (9.81 m/s). Intended launch angle is 30 degrees, find max relative error in s if v and t are subject to relative errors of 10%. I've got: ds/dv = (2vsin2t)/g ds/dt = (2v^2cos2t)/g ds/s = 2dv/v + 2cot2t.dt How do I calculate this if I don't have a value of v? I kinda got to another step (which is still wrong I think), which is... ds/s = 2v/10v + (2cot(2t).dt)/10 where I thought maybe the v's cancelled. Any help would be appreciated.