1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Total mechanical energy

  1. Nov 5, 2007 #1
    I have no clue in solving this question, can somebody help me?
    Last edited: Nov 5, 2007
  2. jcsd
  3. Nov 5, 2007 #2


    User Avatar
    Science Advisor
    Homework Helper

    what have you tried so far?.....
  4. Nov 5, 2007 #3


    User Avatar
    Staff Emeritus
    Science Advisor

    One has two masses A and B, and the mass of A is twice that of B, i.e. mA = 2*mB.

    They are suspended from identical springs and since the mass of A is twice that of B, the deflection of the spring suspending A must be twice that of the spring suspending mass B, because A is twice as heavy.

    The force of the spring is F = kx where k is the spring constant and x is the deflection from rest when zero force is applied to the spring.

    Now the spring mechanical potential energy is [itex]\int_0^x{F(s)}ds[/itex] = 1/2 kx2, so if the deflection of A is 2x and the deflection of B is x, what can one say about the relationship between the mechanical energies?

    Please refer to - http://hyperphysics.phy-astr.gsu.edu/hbase/pespr.html
    Last edited: Nov 5, 2007
  5. Nov 5, 2007 #4
    Hi, I think I am very confused the sign with total mechanical energy....can see here

    Hence using what I am understand
    Treat downward as negative,
    for Mass A
    E=1/2k(2x)^2 - mg(-2x)
    since mg=k(-x), so E=1/2k(2x)^2 - k(-x)(-2x)
    for Mass B
    E=1/2k(x)^2 - mg(-x)
    =1/2k(x)^2 - k(-x)(-x)
    so E_A=4E_B

    Correct...this is the answer...but this will contradict the answer at
    the answer is -1/2kx^2, not 3/2kx^2(cases for mass B)
    What is the problem? I feel very confuse now:(
  6. Nov 5, 2007 #5
    Hi, learningphysics has very kindly posted a long essay in the mentioned thread, will spend some time to digest it, hope that it will shed me some light for this question :)
  7. Nov 5, 2007 #6
    Ok, I think the following make more sense after understanding the explanation of learningphysics

    for Mass A
    =2k(x)^2 - k(2x)(2x)
    for Mass B

    Hence E_A=4E_B

    Is it?
    Last edited: Nov 5, 2007
  8. Nov 5, 2007 #7
    By the way, what I understand from the question is:
    Two blocks are hung by two springs separately, ie each block is hung by one spring, not sure is it correct...although the answer is correct.
  9. Nov 5, 2007 #8


    User Avatar
    Homework Helper

    yes, looks perfect to me.
  10. Nov 5, 2007 #9


    User Avatar
    Homework Helper

    yes, each is balanced by one spring separately...

    only difference from what you said is that the masses are on top of springs that are being compressed... but that makes no difference mathematically...
  11. Nov 5, 2007 #10
    I see, thanks for the confirmation and correction :)
    Last edited: Nov 5, 2007
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook