- #1

leftdalltheway

- 6

- 0

So um here's the problem..

A high school discus thrower rotates at an average angular acceleration of 895 degrees/sec^2 for 1.25 sec. The 2kg discus is realeased 0.87 meters away from the axis of rotation at his spine, at an angle of 30 degrees above the horizontal. The release point is 0.32 meters in front of the throwing circle, and the release height is 1.72 meters above the ground. THe throw is measued from the front of the throwing circle to the mark the discus makes in the ground at landing.

So I figured out the total distance of the throw which is 28.49

But i need to figure out the total momentum of the discus on landing.

Now I know P=mv, so i calculated 2kg * 16.99m/s (that'S the velocity i got). But I know this isn't the asnwer because I have to find out what the velocity is from the peak of the throw to the landing...I don't know how to do this! please help me!