A ball is hit at an angle [tex]\theta[/tex] to the horizontal, from the base of a hill [tex] \phi [/tex] degrees in incline. The ball strikes the hill at a horizontal distance [tex]x[/tex] measured from the launch point. Determine the value of [tex] \theta[/tex] that will result in the largest possible value of [tex] x [/tex].(adsbygoogle = window.adsbygoogle || []).push({});

well i started out finding the vertical displacment to be [tex] x\tan\phi [/tex]

then i put that in the basic [tex]S_{y} = V_{i}sin\theta t + \frac{1}{2}-9.8t^2 [/tex] of corse [tex]S_{y} = xtan\phi[/tex]. now i am stumped on what to do. please help!!!

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# Tough calc projectile Q w/ incline. HELP

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