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Tough inclined plane problem

  1. Aug 9, 2014 #1
    1. The problem statement, all variables and given/known data
    EDIT: I have solved it entirely myself.


    2. Relevant equations



    3. The attempt at a solution
     
    Last edited: Aug 9, 2014
  2. jcsd
  3. Aug 9, 2014 #2

    haruspex

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    Even so, you are required to post your attempt, so far as it goes.
     
  4. Aug 9, 2014 #3
    I have worked it out entirely using my own self-determined methods.
     
    Last edited: Aug 9, 2014
  5. Aug 9, 2014 #4
    Without friction the initial KE should equal the final PE.
     
  6. Aug 9, 2014 #5

    HallsofIvy

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    With friction, final PE should equal initial KE minus energy lost to friction- the friction force times the distance traveled.
     
  7. Aug 9, 2014 #6
    So :

    The initial KE - the final PE = the energy lost to friction
    = ( ½ * m * v ² ) - ( m * g * h )
    ( Joules )

    Over the length of the incline, the energy lost to friction = ( constant ) friction force * distance travelled
    ( the length of the incline = 22.0 / ( sine 2.5 ° ) )

    So, then, the friction force must equal ( ( initial KE ) - ( final PE ) ) / distance travelled

    Comments please.
     
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