- #1
Zorba
- 77
- 0
I am trying to figure out which substitution to use to get this integral done:
[tex]\int \frac{du}{\sqrt{u-u^2} \cdot (1+ub)}[/tex]
When I plug it into Mathematica I get:
[tex]\sqrt{\frac{4}{b+1}} \cdot \texttt{arctan} \left ( \sqrt{\frac{(b+1)u}{1-u}} \right )[/tex]
Any ideas about a suitable substitution?
[tex]\int \frac{du}{\sqrt{u-u^2} \cdot (1+ub)}[/tex]
When I plug it into Mathematica I get:
[tex]\sqrt{\frac{4}{b+1}} \cdot \texttt{arctan} \left ( \sqrt{\frac{(b+1)u}{1-u}} \right )[/tex]
Any ideas about a suitable substitution?