1. The problem statement, all variables and given/known data A uniform, solid cylinder of mass M and radius R rotates on a frictionless horizontal axle. Two equal masses hang from light/weightless cords wrapped around the cylinder. If the system is released from rest, find: A. The tension in each cord. B. The acceleration of each mass after the masses have descended a distance of H. 2. Relevant equations Torque=T(tension)R Torque=I x Alpha T=mg-ma T=Torque/R Alpha=A(tangential)\R I=((1/2)mr^2) 3. The attempt at a solution Based on the relevant equations, I deduced that the tangential acceleration is the downwards acceleration since it is perpendicular to the radius. Combining equations as follows I retrieved my findings for a. T=(I x Alpha)\R TR=(I x Alpha) TR=(Ia)\R TR^2=Ia (TR^2)\I=a (TR^2)\((1\2)mr^2)=a (2T)\m=a I don't know what the answer is as it is not in the back of the book nor was it given during class so I don't know how far or close I am to the answer. If I'm right, let me know. If I'm wrong, it would be greatly appreciated if you could show me where I went wrong or if I was forgetting something.