# Tough torques problem

1. Aug 7, 2007

### avsj

1. The problem statement, all variables and given/known data

Two cables are used to support a 24kg mass on 1.6 m long 8.0 kg unifrom horizontal beam. One cable is on each end of the beam and the mass is 0.6m from the right cable. What is the tension in the right cable?

2. Relevant equations
t=Fd
Fg= mg

3. The attempt at a solution

I really dont know where to set my pivot point.... I have tried multiple approaches.. the answer is 190 N. How do I separate the torque caused by the mass between the two cables?

Thanks,

Aneil

2. Aug 7, 2007

### Staff: Mentor

Since you just need to find the tension in the right cable, pick the left side of the beam as your pivot point.

What forces act on the beam+masses? Where do they act? What torque does each force produce about your chosen pivot point? For equilibrium, what must the net torque be about any point?

3. Aug 7, 2007

### avsj

Thanks Doc Al, seems simple in hindsight but you got me on the right track...:D Great help:)