a uniform 2kg horizontal beam is 50cm long is bolted to a wall and supports a 5kg sign. calculate the tourqe produced by the combined weight of the beam and the sign about where it is mounted to the wall.
tourqe = F x Perpendicular distance
The Attempt at a Solution
So im using the wall as the pivot point making the distance to the centre of mass of the beam 0.25m.
the tourqe of the beam= (9.8x2)x(0.25)
The tourqe of the sign= (9.8x5)x(0.5)
And to get the total tourqe i have added these togther to get 29.4Nm
But my course book says the answer is 118Nm?? i know this is a pretty simple question but i cant pick up my error