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## Homework Statement

An accident victim with a broken leg is being placed in traction. The patient wears a special boot with a pulley attached to the sole. The foot and boot together have a mass of m = 4.0 kg, and the doctor has decided to hang a 6.0 kg mass from the rope. The boot is held suspended by the ropes, as shown in the image, and does not touch the bed.

*a)*Determine the amount of tension in the rope by using Newton's laws to analyze the hanging mass.

*b)*The net traction force needs to pull straight out on the leg. What is the proper angle θ for the upper rope?

*c)*What is the net traction force pulling on the leg?

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I have seen other people post this problem with different circumstances/variables, however, when I plug in my variables and try to make it work for my given problem I am finding myself stuck.

## Homework Equations

w=mg

## The Attempt at a Solution

*a)*[/B] Find the tension on the rope:

w = mg

= (6.0 kg)(9.8 [gravity])

w = 58.8 N (rounded to 59N)

*tension on the rope*

**Find the proper angle for the upper rope:**

*b)*First I try to find the amount of force on the boot. using the same equation

w = mg

= (4.0kg)(9.8)

= 39.2 N of force acting on the boot

Then I take the sine to find the correct angle, right? So,

58.8 sin(θ) = 39.2 + 58.8 sin(15°)

θ = 54.42°

But I know that is incorrect. My book says that it's actually 67.8°. How? What am I doing wrong?

**I cant even get to this point without answering**

*c)**(b)*.