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- Thread starter Aashish sarode
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Chestermiller

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What do you get if you apply an angular momentum balance to the wheel?

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will you please elaborate your question?What do you get if you apply an angular momentum balance to the wheel?

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less bcz torque =force*radius and in this case sprocket radius is less than that of wheels

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Chestermiller

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The sprocket torque minus the tire torque is equal to the wheel moment of inertia times the angular acceleration of the wheel. If the bike is not accelerating, then the sprocket torque is equal to the wheel torque. (I assume that by sprocket torque, you are referring to the torque applied by the chain to the sprocket).will you please elaborate your question?

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Chestermiller

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If the car isn't accelerating, it sure is the same. The moments (torques) must balance. Just take the wheel and attached sprocket as a free body.

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Where [itex]I[/itex] is the inertia of the sprocket-axle-wheel-tire assembly and [itex]\alpha[/itex] is the rotational acceleration of the assembly.

If there is no acceleration ([itex]\alpha = 0[/itex]), then the tire torque is exactly the same as the sprocket torque. Otherwise, in typical assembly, the inertia should be small enough to consider that they are both practically the same as well (although, not necessarily a negligible difference).

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Chestermiller

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cjl

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The torque is absolutely the same. The force, however, is not, since as you pointed out earlier, torque is force multiplied by radius.

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power=torque*angular velocity , since pThe sprocket torque minus the tire torque is equal to the wheel not accelerating, then the sprocket torque is equal to the wheel torque. (I assume that by sprocket torque, you are referring to the torque applied by the chain to the sprocket).

less bcz torque =force*

hmm ,power remains constant i.e power =torque *angular velocity ,angular velocity for sprocket and wheel is same so torque nust be equal. Thank u all.The torque is absolutely the same. The force, however, is not, since as you pointed out earlier, torque is force multiplied by radius.

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billy_joule

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That is not always true, there can be losses between the sprocket and the wheel; friction at a bearing, losses through a CV joint, a dragging brake pad etc etc. Power still remains constant but not all of it makes it to the wheel:hmm ,power remains constant i.e power =torque *angular velocity ,angular velocity for sprocket and wheel is same so torque nust be equal. Thank u all.

P

P

Whether these losses are small enough to be ignored depends on your system.

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