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Trajectory- Find the angle

  1. Nov 3, 2009 #1
    1. The problem statement, all variables and given/known data
    A ball is thrown with initial velocity 20m/sec against a wall 50 meters away. It is released from a height of 1.8 meters, and hits the wall at 1.2 meters. Find the angle of the throw.


    2. Relevant equations
    50=20t*cos(theta)
    -.6=20t*sin(theta)-.5(9.8)(t^2)


    3. The attempt at a solution
    Is it possible to solve this problem without knowing t(time between launch and hitting the wall)? Thanks for the help, I need to know if I'm missing a formula or something.
     
  2. jcsd
  3. Nov 4, 2009 #2
    im not 100% sure about this but you dont need to find t, you just need to rearange your 1st equatoin so you have t=... and then substitute that into your 2nd equation and then you can find theta. maybe
     
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