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Trajectory of a missile

  1. Feb 1, 2012 #1
    1. The problem statement, all variables and given/known data
    In testing a missile defense system, a missile is red from the ground on a
    trajectory that would directly hit a bunker some distance away. When the missile is
    at the top of the trajectory, a laser light from the bunker ignites fuel in the missile
    and the missile disintegrates into two pieces, one twice as massive as the other. The
    pieces reach the ground nearly simultaneously, 60m apart from each other.

    (a) By how much does the larger piece miss the bunker? Hint: Consider motion of
    the center of mass.
    (b) By how much does the smaller piece miss the bunker?
    (c) How important is the information that the fuel ignited at the top of the trajectory?

    2. Relevant equations

    3. The attempt at a solution


    so far I figured out this:
    http://imgur.com/MdLrl
    http://imgur.com/YqBet

    I know that I need one more equation to get all the unknowns.
    the homework is due in 5 hours if any one could help I would love you forever.
     
  2. jcsd
  3. Feb 2, 2012 #2
    This looks like a conservation of momentum problem, more than a kinematics problem.

    For part (c), the rocket is tangent to the x-axis (i.e., going horizontally) when the laser zaps it, so there should be no change in the y components of the velocity or the acceleration when it blows. Both pieces should have the same velocity and acceleration in that dimension. At max height, the y component of velocity is zero, so all of the momentum is in the x direction.

    If we use your definition of the initial mass as 3m and the two pieces as m and 2m, and define the initial velocity as v0, then conservation of momentum is

    p0 = p1 + p2

    where

    p0 = m0v0 = (3m)v0

    Let's define the change in velocity of the small piece as v1 and the change in velocity of the larger piece as v2. This is a bit different than the usual notation, but there's a method to my madness.

    Define (v0 + v1) as the velocity of the small piece and (v0 + v2) as the velocity of the big piece. v1 and v2 are the changes in velocity from the fuel exploding. Intuitively, one of these should be the opposite of the other as they fly apart, but let's leave the signs as positive for now.

    So, p1 = m (v0 + v1) and p2 = 2m (v0 + v2)

    The conservation law is then p0 = p1 + p2 or

    3m(v0) = m (v0 + v1) + 2m (v0 + v2)

    Multiply it out:

    3m(v0) = m(v0) + m(v1) + 2m(v0) + 2m(v2)

    Collect similar terms:

    3m(v0) = 3m(v0) + m(v1) + 2m(v2)

    Subtract 3m(v0) from both sides:

    0 = m(v1) + 2m(v2)

    Divide by m:

    0 = v1 + 2(v2)

    Subtract 2(v2) from both sides

    - 2(v2) = v1, or v1 = -2(v2)

    So, intuition and our signs match up. The little piece's change in velocity is opposite in direction to the big one and its velocity changes twice as much as the big piece changes.

    That should be a big enough hint for you.
     
    Last edited: Feb 2, 2012
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