- #1
Taufik
Suppose a particle is moving in an X-Y plane. It's velocity in X direction will be dx/dt and in Y direction will be dy/dt. Suppose at a certain point it's velocity in x direction is zero and in y direction is also zero. Then, dx/dt =0 & dy/dt =0 at that point.
Now, what will the trajectory be near that point? Since dy/dx = 0/0, which is not defined, therefore the slope at that point is not defined. So, will it be something like a sharp edge or a smooth curve?
Now, what will the trajectory be near that point? Since dy/dx = 0/0, which is not defined, therefore the slope at that point is not defined. So, will it be something like a sharp edge or a smooth curve?