A projectile fired from ground level at 25 m/s hits the ground 31.25 m away. At what angle was it fired? I wrote equations for t for both x and y t = delta x / velocity x t = 2 * viy/a and set them equal to each other to eliminate t and replaced velocityx with cos(theta)*25 and replaced velicityinitialy with sin(theta)*25 delta x / cos(theta)*25 = 2*sin(theta)*25/a 25 / cos(theta)*25 = 2*sin(theta)*25/9.81 sin(theta) * 25 * cos(theta)*25 = 153.28 My trig is not that good. How do I continue? Or is this even the right way to tackle this proble? Is there an easier way?