- #1
dramadeur
- 19
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I don't quite get, where does the V0x=v * d/(sqrt(d^2+(h-y0)^2) come from?
also, what does (h-y0) equal to? t/v0y?
dramadeur said:where does the V0x=v * d/(sqrt(d^2+(h-y0)^2) come from?
dramadeur said:what does (h-y0) equal to? t/v0y?
V0x, also known as initial horizontal velocity, is the initial velocity of a dart in the horizontal direction. It is important in calculating dart trajectory because it determines the distance the dart will travel in the x-axis.
V0x can be calculated by multiplying the initial velocity of the dart by the cosine of the launch angle.
V0x affects the trajectory of a dart by determining the distance it will travel in the x-axis. A higher V0x will result in a longer horizontal distance, while a lower V0x will result in a shorter distance.
No, V0x cannot be changed during the flight of a dart. It is a constant value determined by the initial conditions of the dart, such as the thrower's arm speed and angle of release.
Yes, there are other factors that can affect dart trajectory, such as air resistance, wind speed and direction, and the weight and shape of the dart. These factors can alter the path of the dart and should be taken into consideration when calculating its trajectory.