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A high diver leaves the end of a 5 m high diving board and strikes the water 1.3s later 3 m beyond the end of the board. Considering the diver as a particle,d etermine a) her initial velocity, B. the maximum height reached and c. the velocity withwhich she enters the water.

I tried using these formulas: Vx = Vx0, x=x0+Vx0t

Vy = Vy0-gt, y = y0 + Vy0t- .5gt^2, v^2y = V^2y0 -2g(y-y0)