(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 60 kg person jumps from a platform onto a trampoline 10 m below, stretching it 1.0 m from its initial position. Assumin that the trampoline behaves like a simple elastic spring, how much will it stretch if the same person jumps from a height of 20 m?

2. Relevant equations

Law of Conservation of Energy

Ek = 0.5mv^2

Eg = mgh

Ee = 0.5kx^2

Fx = kx

3. The attempt at a solution

Really didn't understand the question at all. I figured since the guy is jumping of the platform, velocity at that instance would be 0. If the guy landed on the trampoline, his velocity would be 0 (but i don't know about this). The equillibrium of spring is 0 when the guy jumps of platform so there is no elastic potential. I am guessing there is some gravitational potential as the platform is above the trampoline. But I am consistently getting the wrong answer. The answer is 1.4 m. How would you get that?

Thanks, I appreciate the help.

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# Trampoline Question

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