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Transcendental numbers

  1. Apr 20, 2012 #1
    Is there a proof that there exist (or does not exist) integers m and n such that [itex]{e^{m/n}} = \pi[/itex]? How would one prove such a statement?
     
  2. jcsd
  3. Apr 20, 2012 #2
  4. Apr 20, 2012 #3
    Along those lines, it's unknown whether [itex]e + \pi[/itex] is rational or irrational. If it turned out to be rational, that would be amazing, wouldn't it?
     
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