Transfer of spring energy

  • Thread starter Ry122
  • Start date
  • #1
565
2
A block of mass 0.250 kg is placed on top of a light vertical spring of constant k = 5200 N/m and is pushed downward so that the spring is compressed 0.093 m. After the block is released, it travels upward and then leaves the spring. To what maximum height above the point of release does it rise?

my attempt:
energy in spring = (.5)5200(.093)^2=22.4874J
Weight of block = .250x9.8=2.45N
W=fxs
22.4874=2.45xs
s=9.178

What am i doing wrong?
 

Answers and Replies

  • #2
327
1
use the Energy formula involving initial and final energy.
 
  • #3
565
2
what is it?
 
  • #4
3,003
2
What makes you think you are doing these wrong? I got the same answer. Same thing with your centrifugal force problem. They both look good to me.
 
  • #5
565
2
it was wrong because it asks how high does the block go above the spring so i had do minus the length of compression of the spring from the final answer.
 

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