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Transform to linear

  1. Sep 5, 2010 #1
    how do i transform this to linear
    [tex] 2xyy' = 4x^2 +3y^2 [/tex]
    using substitution
     
  2. jcsd
  3. Sep 5, 2010 #2

    HallsofIvy

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    This can be written as
    [tex]\frac{dy}{dx}= \frac{4x^2+ 3y^2}{2xy}= 2\frac{x}{y}= \frac{3}{2}\frac{y}{x}[/tex]

    Try the substitution u= y/x.
     
  4. Sep 5, 2010 #3
    so if u=y/x would this be right? [tex] \frac{du}{dx}= \frac{-dy}{dx} \frac{1}{x^2} [/tex]

    you third equal sign should be a + sign i believe
     
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