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Transformation fun!

  1. Mar 29, 2008 #1
    Describe a sequence of transformations that would transform the graph of

    y = 5cos3x into y = cos(3x + 6)
  2. jcsd
  3. Mar 29, 2008 #2
    The 5 in front of the cos(3x) (I assume it's cos(3x), be more clear next time) turned into a 1 in the second function. What does this mean?

    The (3x) turned into a (3x + 6). What does this mean?

    Recall the definitions of translations and expansions/compressions.
  4. Mar 29, 2008 #3
    Remember that:

    Let f(x), ang g(x), be two functions. Then if g(x)=f(x)+k, it means that g(x) is simply the function f(x) shifted up/down wards for k units.
    g(x)=f(x+k), it means that g(x) is simply the function f(x) shifted horizontally for k units, either to the right or to the left, depending on the sign of the constant k.
    g(x)=kf(x), it means that g is simply the function f, shrinked or extended(or how do you say it) vertically, depending whether |k|>1, or |k|<1.
    g(x)=f(kx), is again the function f either extended, or shrinked horizontally, depending on the value of the constant k.

    I hope this helps a lill bit.
  5. Mar 29, 2008 #4


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    Remember that any change before the given function is applied (in this case 5cos(3x)) is a change in x and any function after the function is a change in y.
    changing 5cos(3x) to cos(3x+6) involves 3 changes:
    1) Add 6 to 3x. That is, change 3x to 3x+ 6= 3(x+2) or x to (x+ 2). That's the first transformation.
    2) change y= cos(3x+6) to y= 5cos(3x+6) or y to 5y. That's the second transformation.
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