- #1

Higgsono

- 93

- 4

Given a scalar function, we consider the following transformation:

$$\delta f(x) = f'(x') - f(x) $$ Given a coordinate transformation $$x' = g(x)$$

But since ##f(x)## is a scalar isn't it true that ##f'(x') = f(x) ##

Then the variation is always zero? What am I missing?

$$\delta f(x) = f'(x') - f(x) $$ Given a coordinate transformation $$x' = g(x)$$

But since ##f(x)## is a scalar isn't it true that ##f'(x') = f(x) ##

Then the variation is always zero? What am I missing?

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