- #1
aisha
- 584
- 0
Rewrite Function PLZ HELP
I have a question for translation of functions
it says the equation of the image is [tex] -2 \sqrt(3x-12) -5 [/tex]
(note: sorry the square root should be over all of the 3x and -12 only -5 is outside of square root)
1) the first questions said what is the base function? I wrote [tex] \sqrt(x) [/tex]
2) the second question said describe the series of transformations, so i wrote
Vertical stretch by a factor of 2, horizontal compression by a factor of 1/3, reflection in the x-axis, vertical translation 5 units down, horizontal translation 4 units left.
3) It says write the function into y=af[k(x-p)]+q form
I got [tex] -2\sqrt(3(x-(-4)) -5 [/tex] (note: again square root is over everything in brackets except -5 )but i think this is wrong since there is a square root in my answer and no square root in the form that they want. Can someone help me out please Is only number 3 wrong? How do I rewrite the equation in the correct form?
I have a question for translation of functions
it says the equation of the image is [tex] -2 \sqrt(3x-12) -5 [/tex]
(note: sorry the square root should be over all of the 3x and -12 only -5 is outside of square root)
1) the first questions said what is the base function? I wrote [tex] \sqrt(x) [/tex]
2) the second question said describe the series of transformations, so i wrote
Vertical stretch by a factor of 2, horizontal compression by a factor of 1/3, reflection in the x-axis, vertical translation 5 units down, horizontal translation 4 units left.
3) It says write the function into y=af[k(x-p)]+q form
I got [tex] -2\sqrt(3(x-(-4)) -5 [/tex] (note: again square root is over everything in brackets except -5 )but i think this is wrong since there is a square root in my answer and no square root in the form that they want. Can someone help me out please Is only number 3 wrong? How do I rewrite the equation in the correct form?
Last edited: