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I have a question for translation of functions

it says the equation of the image is [tex] -2 \sqrt(3x-12) -5 [/tex]

(note: sorry the square root should be over all of the 3x and -12 only -5 is outside of square root)

1) the first questions said what is the base function? I wrote [tex] \sqrt(x) [/tex]

2) the second question said describe the series of transformations, so i wrote

Vertical stretch by a factor of 2, horizontal compression by a factor of 1/3, reflection in the x-axis, vertical translation 5 units down, horizontal translation 4 units left.

3) It says write the function in to y=af[k(x-p)]+q form

I got [tex] -2\sqrt(3(x-(-4)) -5 [/tex] (note: again square root is over everything in brackets except -5 )but i think this is wrong since there is a square root in my answer and no square root in the form that they want. Can someone help me out please Is only number 3 wrong? How do I rewrite the equation in the correct form?

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# Homework Help: Transformation of function

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