# Transformation problem

I was just wondering how I can start out with a parallelepiped only cutting 4 faces vertically, at right angles to the edges I cut through & rearrange the pieces so that I can get rectangular box so that the volume is the area of the base times the height.

LCKurtz
Homework Helper
Gold Member

I was just wondering how I can start out with a parallelepiped only cutting 4 faces vertically, at right angles to the edges I cut through & rearrange the pieces so that I can get rectangular box so that the volume is the area of the base times the height.
If this is a puzzle where you are trying to re-arrange the pieces to form a rectangular box, I can't help you. Are you aware the volume of a parallelepiped is the already the area of the base times the height?

If this is a puzzle where you are trying to re-arrange the pieces to form a rectangular box, I can't help you. Are you aware the volume of a parallelepiped is the already the area of the base times the height?
Actually the volume of a parallelpiped is a.(bxc)

LCKurtz
Homework Helper
Gold Member

Actually the volume of a parallelpiped is a.(bxc)
You mean |a.(bxc)|.

Yup, no negative volumes here. :)

How could you do it if you had say a loaf of bread or a paper model.