Transformation problem

  • Thread starter squenshl
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  • #1
squenshl
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I was just wondering how I can start out with a parallelepiped only cutting 4 faces vertically, at right angles to the edges I cut through & rearrange the pieces so that I can get rectangular box so that the volume is the area of the base times the height.
 

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  • #2
LCKurtz
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I was just wondering how I can start out with a parallelepiped only cutting 4 faces vertically, at right angles to the edges I cut through & rearrange the pieces so that I can get rectangular box so that the volume is the area of the base times the height.

If this is a puzzle where you are trying to re-arrange the pieces to form a rectangular box, I can't help you. Are you aware the volume of a parallelepiped is the already the area of the base times the height?
 
  • #3
jav
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If this is a puzzle where you are trying to re-arrange the pieces to form a rectangular box, I can't help you. Are you aware the volume of a parallelepiped is the already the area of the base times the height?

Actually the volume of a parallelpiped is a.(bxc)
 
  • #4
LCKurtz
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Actually the volume of a parallelpiped is a.(bxc)

You mean |a.(bxc)|.
 
  • #5
jav
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Yup, no negative volumes here. :)
 
  • #6
squenshl
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How could you do it if you had say a loaf of bread or a paper model.
 

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