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Transformer Impedance/Ratio

  1. Jun 24, 2009 #1
    1. The problem statement, all variables and given/known data

    See attached for a view of the problem

    Variables a=transformation ratio= 1/5
    Ip=2Amps
    ZL=2 ohm resistor

    2. Relevant equations
    Q1 : Find the current magnitude of the current IL and the Voltage VL
    Q2 : Find the input impedence.


    3. The attempt at a solution

    OK, my question is variable a, which is the transformation ratio is 1/5. From my reading the transformation ratio is equal to the number of turns of the primary divided by the number turns of the secondary...

    How

    so a= NP/NS = 1/5

    NP =1 turn Per NS =5

    Then, the input impedence should be Rin = A^2ZL

    Rin = (1/5)^2(2 ohms)

    Rin = .08 ohms

    Does that look correct for the impedance?


    Then for the current for IL, a = Is/Ip or Is = (a)(Ip) or Is = .4 amps


    does it look correct?

    Thanks for any response :)
     
  2. jcsd
  3. Jun 24, 2009 #2

    negitron

    User Avatar
    Science Advisor

    Yes, these figures look correct. You should be able to readily calculate VL now.
     
  4. Jun 24, 2009 #3
    Awesome :) thanks for your response :)
     
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