Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Transforming the electric field

  1. Sep 8, 2009 #1
    Suppose I have two charges of mass m'_c stationary in S' separated by a constant distance and one of the charges is released at time t' and accelerates with acceleration _a' to a velocity du' a time dt' later. The force is then just m'_c*du'/dt'. If I transform this event to frame S, then the velocity is transformed using the addition of velocities formula and dt' is transformed using the LT giving:

    du = (V + du')/(1 + Vdu'/c^2) - V

    dt = gamma(dt' + dx'V/c^2)
    = gamma(dt' + 1/2 _a dt'^2 V/c^2)
    = gamma dt'.

    So the acceleration in S is:

    ((V + du')/(1 + Vdu'/c^2) - V)/gamma

    Is this correct so far?

    I need to transform m'_c to m_c to work out the equivalent force in S causing the moving charge to accelerate. How do I do this?

    How do I work out the force on a stationary charge in S placed at the point where the accelerating charge is?

    Thanks for your interest.
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted

Similar Discussions: Transforming the electric field