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Transients in DC Circuits - calculating rate of change after specific time period

  • Engineering
  • Thread starter Foilist
  • Start date
  • #1
10
1
The attached document contains the question and the answers I have calculated. I am confident that I have answered them correctly however another pair of eyes is always useful.


The problem I have is with part f - Rate of change of current at the instant the switch is closed on position 2. I know that the current needs to reverse, and that the inductor will oppose this reversal, until such time as eventually the steady-state current calculated at part d will be reached, however I'm at a loss as to where to start the calculations.
 
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Answers and Replies

  • #2
CEL
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0
You have an expression for the current at every instant t 0<t<0.72s.
If you differentiate that expression you have di/dt. Replace t by 0.72 and you have the rate of change at that instant.
Replace t by 0 and check the result you obtained in item e.
 

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