Solving Transistor Problem: Find Voltage Across Base & Emitter

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In summary, the given diagram shows an NPN transistor circuit with a lamp, capacitor, and resistor. When the circuit is switched on, the voltage across the capacitor gradually increases and eventually reaches a point where it starts to turn on the transistor through the 50k ohm resistor. This causes some of the charging current to be diverted to the base of the transistor, slowing down the RC charging time constant. The circuit stabilizes when some current flows into the base and some collector current is pulled down through the load. The voltage across the capacitor and the transistor's Beta value are variables in determining the initial RC charge-up period, Vbe turn-on period, and final stabilized circuit voltages and currents.
  • #1
Pseudo Statistic
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http://www.brokendream.net/xh4/circDiag.png
We're given this diagram with a question and asked: (NPN transistor)
a) Describe what would happen when the circuit is switched on.
b) Explain why this happens.
c) What is the time constant for the capacitor in this circuit?
d) What is the purpose of the 50k ohm resistor?

I'm having problems answering a.
If the voltage across the base and emitter >= 0.6A, THEN the lamp would be lit..
However, I have ABSOLUTELY NO CLUE how to find the voltage across the base and emitter! Can someone show me how? (I never learned this in class, with respect to transistors :()
Thanks.
 
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  • #2
When they say "switched on", they mean that the top rail goes from 0V to 6V pretty much instantaneously. Now, the voltage across the 2200uF cap can't change instantaneously, so there will be an RC ramp-up of the voltage across it until the voltage gets high enough to start to turn on the transistor through the 50k resistor. At that point, some of the RC charging current gets diverted over to the base of the transistor, so the RC charging time constant changes (slows down). The circuit will stabilize at a point where some current is flowing into the transistor base, and some collector current is being pulled down through the load.

Now, use the Beta of the transistor as one of the variables, call the voltage across the cap V1, the voltage at the collector Vc, and the voltage at the base Vb. Take a first cut at the equations for the initial RC charge-up period, then the Vbe turn-on period, and the final stabilized circuit voltages and currents. Show us what you get!
 
  • #3


a) When the circuit is switched on, the transistor will start conducting current from the collector to the emitter. This will allow current to flow through the lamp, causing it to light up. The amount of current that flows through the transistor is determined by the voltage across the base and emitter.

b) This happens because transistors are semiconductor devices that can amplify and switch electronic signals. In this circuit, the base-emitter junction of the transistor acts as a diode and requires a minimum voltage of 0.6V to allow current to flow through it. Once this voltage is reached, the transistor will start conducting and allow current to flow from the collector to the emitter, turning on the lamp.

c) The time constant for the capacitor in this circuit can be calculated using the formula T = RC, where R is the resistance of the 50k ohm resistor and C is the capacitance of the capacitor. Without knowing the value of the capacitor, it is not possible to determine the time constant.

d) The 50k ohm resistor is used to limit the current flowing through the base of the transistor. This is important because too much current could damage the transistor. The resistor also helps to stabilize the voltage at the base, ensuring that the transistor is not overloaded with current.
 

1. What is a transistor?

A transistor is a semiconductor device that is used to amplify or switch electronic signals. It is made up of three layers of material, usually silicon, and has three terminals: the base, emitter, and collector.

2. How do I find the voltage across the base and emitter of a transistor?

To find the voltage across the base and emitter of a transistor, you will need to use Ohm's Law, which states that the voltage (V) is equal to the current (I) multiplied by the resistance (R). In this case, the current is the current flowing through the base-emitter junction and the resistance is the base-emitter resistance of the transistor, which can be found in the transistor's datasheet.

3. What factors affect the voltage across the base and emitter of a transistor?

The voltage across the base and emitter of a transistor is affected by the base-emitter resistance, the current flowing through the base-emitter junction, and the voltage drop across the collector-emitter junction. It is also affected by the temperature and the type of transistor being used.

4. Can I use a multimeter to measure the voltage across the base and emitter of a transistor?

Yes, you can use a multimeter to measure the voltage across the base and emitter of a transistor. Set the multimeter to measure DC voltage and connect the positive lead to the base terminal and the negative lead to the emitter terminal. Make sure the transistor is properly biased and powered on before taking the measurement.

5. Why is it important to know the voltage across the base and emitter of a transistor?

The voltage across the base and emitter of a transistor is important because it determines the amount of current flowing through the base-emitter junction and affects the overall performance of the transistor. It is also crucial in designing and troubleshooting electronic circuits that use transistors.

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