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Translation of inclined bar

  1. Sep 27, 2010 #1
    I have a question on pure translation of inclined bar. The problem statement is:
    A homogenous slender bar with a mass of 4 kg and a length of 500mm being pushed along the smooth horizontal surface by a horizontal force P=60N. Determine the angle θ for translation. What is the accompanying acceleration? (FBD and kinetic diagram attached)

    I used the following equations:
    ⅀MG=0 (since rod is in translation)
    The results
    θ = 33.4°
    a = 15m/s2
    My question is, there exists a moment about point A equal to 8.26Nm. What is the physical meaning of this moment? Would not the rod rotate about A due to this moment? Requesting for help please.

    Attached Files:

  2. jcsd
  3. Sep 27, 2010 #2
    If my question has already been discussed earlier, request some of you to give link to those threads.
    Thanks in advance.
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