I have a question on pure translation of inclined bar. The problem statement is:
A homogenous slender bar with a mass of 4 kg and a length of 500mm being pushed along the smooth horizontal surface by a horizontal force P=60N. Determine the angle θ for translation. What is the accompanying acceleration? (FBD and kinetic diagram attached)
I used the following equations:
⅀MG=0 (since rod is in translation)
The Attempt at a Solution
The results i arrived at are:
θ = 33.4°
a = 15m/s2
My question is, there exists a moment about point A (point of contact between bar and contact surface) equal to 8.26Nm. What is the physical meaning/significance of this moment? Would not the rod rotate about A due to this moment? Requesting for help please.
If my question has already been discussed earlier, request some of you to give link to those threads.
Thanks in advance.
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