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Translational Kinetic Energy

  1. Dec 9, 2009 #1
    1.Find the total translational kinetic energy of 0.5 L of oxygen gas held at a temperature of 0°C and a pressure of 1.3 atm.


    2.
    R = 8.314

    PV=nRT
    PV=NkT

    K=(.5*m*v^2)

    Translational Kinetic Energy = T=(2/3)(1/k)[(.5)mv^2]


    3.
    The problem says to express the total translational kinetic energy of the oxygen gas by combining the expression for the translational kinetic energy and the ideal-gas law to obtain an expression for K in terms of the pressure and volume of the gas.
    I tried subsitituting T= PV/nR to T=(2/3)(1/k)[(.5)mv^2] but I am not sure if I am on the right track.
     
  2. jcsd
  3. Dec 9, 2009 #2
    You can use PV = nRT to find the mols of oxygen gas you have. Then, you can use the translational kinetic energy equation for gasses, K = (3/2)nRT, to find K.
     
  4. Dec 9, 2009 #3
    Oh. So i need to find the moles using the ideal gas law then plug it in to the K equation. I was over thinking the whole problem.
     
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