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Translational Speed

  1. Mar 12, 2007 #1
    A bowling ball encounters a 0.760-m vertical rise on the way back to the ball rack, as the drawing illustrates. Ignore frictional losses and assume that the mass of the ball is distributed uniformly. The translational speed of the ball is 7.88 m/s at the bottom of the rise. Find the translational speed at the top.
     
  2. jcsd
  3. Mar 13, 2007 #2

    Kurdt

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    You really need to show some working before you can receive any help. As a hint you can think about the conservation of energy.
     
  4. May 5, 2007 #3
    HOW IS THE EQUATION SETUP FOR THIS PROBLEM
     
  5. May 5, 2007 #4
    kE1+PE1=KE2+PE2
    1/2(MKG)(7.880)^2+(MKG)(9.8)(.76M)=1/2MKG(V)^2+MKG(9.8)(X)
     
  6. May 5, 2007 #5
    WILL THIS EUATION WORK FOR THE SPEED
     
  7. May 5, 2007 #6

    hage567

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    You're on the right track, but you mixed up your gravitational potential energy terms a bit. If you take the bottom of the rise as your reference point, what is the gravitational potential energy of the ball before it goes up the rise?
     
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