Transverse wave in a string

  • #1
75
0

Homework Statement



http://puu.sh/frpk5/eae7bce2e3.png [Broken]

Homework Equations



v = sqrt(T / (m / L));

The Attempt at a Solution



7.86 g / cm^3 = 7860 kg / m^3

T = v^2 * m/L

T = 160 ^ 2 * 7860 which is a huge number

I have no idea where the diametre plays a part.
 
Last edited by a moderator:

Answers and Replies

  • #2
Nathanael
Homework Helper
1,650
245
m/L ≠ 7860 (check the dimensions)
 
  • #3
75
0
m/L ≠ 7860 (check the dimensions)
I'm sorry I really don't understand what you're aiming at. Does it have to do with the m^3?

I know it's mass per unit length but how would I go from 7860 kg / m^3 to what I need? Thank you.
 
  • #4
Nathanael
Homework Helper
1,650
245
I'm sorry I really don't understand what you're aiming at. Does it have to do with the m^3?
You were given the mass per volume, but you want to know the mass per length. You used the mass per volume where you should have used the mass per length.

I know it's mass per unit length but how would I go from 7860 kg / m^3 to what I need? Thank you.
Consider a steel wire with a larger diameter. (They are both steel, so the density is the same.) Which one will have the larger mass per length? Or will it be the same? And why?
 

Related Threads on Transverse wave in a string

  • Last Post
Replies
8
Views
1K
  • Last Post
Replies
8
Views
885
  • Last Post
Replies
31
Views
2K
  • Last Post
Replies
1
Views
10K
  • Last Post
Replies
5
Views
3K
Replies
14
Views
20K
Replies
1
Views
2K
Replies
8
Views
4K
Replies
6
Views
581
Replies
1
Views
4K
Top