1. May 3, 2008 #1

   daudaudaudau

   

   If I define a triangle like this
   
   [tex]0\le y\le 1[/tex] and [tex]0\le x\le 1-y[/tex],
   
   then what is
   
   [tex] \lim_{x\rightarrow 1} \frac{y}{1-x}[/tex] ?
   
   As far as I can see, there are many possibilities, depending on how you "approach" [tex]x=1[/tex].

    

   daudaudaudau, May 3, 2008
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3. May 4, 2008 #2

   HallsofIvy

   

   Staff Emeritus

   Science Advisor

   What you are writing doesn't make sense. Since you are taking the limit only as x goes to 1, y is some fixed number between 0 and 1. If [itex]x\le 1-y[/itex] and y is not 1 then x cannot "approach" 1. If y= 1, then, of course, the limit does not exist.

    

   HallsofIvy, May 4, 2008
4. May 4, 2008 #3

   daudaudaudau

   

   Hmm, yeah, maybe it does not make much sense. Fortunately, I was able to fix my problem in another way, which gave a result with no singularities. So I don't have to solve this problem :) Phew.

    

   daudaudaudau, May 4, 2008

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