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Triangle Proof

  1. Feb 24, 2004 #1
    I can't figure out this problem

    Lets take triangle ABC

    B C

    a median (D) goes from A to the midpoint of BC
    a median (E) goes from B to the midpoint of AC

    Prove that triangle AEF = triangle FBD

    Since a median divides up a triangle you know that
    triangle ABD = triangle ADC
    triangle ABE = triangle EBC

    Here is where I'm getting stuck could someone please tell me the next step or two?
  2. jcsd
  3. Feb 24, 2004 #2
    I forgot to mention F is the point where the two medians cross
  4. Feb 24, 2004 #3
    Well, I am not sure what form your answer is supposed to take, but how about this...

    You know that
    ABD = ADC

    Then when you bisect them it follows that:
    (1/2)ABD = (1/2)ADC

    BDF = (1/2)ABD and AEF = (1/2)ADC

    BDF = AEF

    I hope this helps. Let me know.
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