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Triangle Rate Problem

  1. Nov 5, 2004 #1
    Hi, I'm having trouble with this one problem. I've been struggling to do it for hours! Ok maybe mins, but I still can't get the right answer. :frown:

    The altitude of a triangle is increasing at a rate of 3 centimeters/minute while the area of the triangle is increasing at a rate of 3.5 square centimeters/minute. At what rate is the base of the triangle changing when the altitude is 9.5 centimeters and the area is 99 square centimeters?

    The answer I got was 7/3.
     
  2. jcsd
  3. Nov 6, 2004 #2

    mathman

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    Gold Member

    A=area, b=base, h=altitude.

    b=2A/h. Therefore b'=2(hA'-Ah')/h2.

    You do the arithmetic. (I did not get 7/3).
     
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